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1.25=x+x^2
We move all terms to the left:
1.25-(x+x^2)=0
We get rid of parentheses
-x^2-x+1.25=0
We add all the numbers together, and all the variables
-1x^2-1x+1.25=0
a = -1; b = -1; c = +1.25;
Δ = b2-4ac
Δ = -12-4·(-1)·1.25
Δ = 6
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-\sqrt{6}}{2*-1}=\frac{1-\sqrt{6}}{-2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+\sqrt{6}}{2*-1}=\frac{1+\sqrt{6}}{-2} $
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